**Leetcode [283]** - Move Zeros (Java Solution)

**Category:** Easy

**What is used**: Array

## Question

Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

### Example 1:

**Input**: [0,1,0,3,12]

**Output**: [1,3,12,0,0]

#### Note:

- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.

## Solution

I am using **Simple Array** to solve this problem. There are various different methods to solve this problem but this is one the most straight forward and simple way.

I traverse through the array and keep count of non-zero numbers. While iterating through the array, set ** array[count++] = arr[i].** In the end, traverse again to set the remaining elements as zero.

```
class Solution {
public void moveZeroes(int[] nums) {
int count = 0;
int n = nums.length;
for (int i = 0; i < n; i++){
if(nums[i] != 0){
nums[count++] = nums[i];
}
}
for (int j = count; j < n; j++){
nums[j] = 0;
}
}
}
```

#### Time complexity:

The time complexity of this code is **O(n)**

The space complexity of this code is **O(1)**

#### Submission Details:

**Runtime**: 0 ms. Runtime beats 100.00 % of java submissions.

**Memory Usage**: 37.7 MB